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In this case, the compiler cannot differentiate between the two version of MyMeth( ) simply because one uses an out int parameter and the other uses a ref int parameter Method overloading supports polymorphism because it is one way that C# implements the one interface, multiple methods paradigm To understand how, consider the following In languages that do not support method overloading, each method must be given a unique name However, frequently you will want to implement essentially the same method for different types of data Consider the absolute value function In languages that do not support overloading, there are usually three or more versions of this function, each with a slightly different name For instance, in C, the function abs( ) returns the absolute value of an integer, labs( ) returns the absolute value of a long integer, and fabs( ) returns the absolute value of a floating-point value Since C does not support overloading, each function must have its own unique name, even though all three functions do essentially the same thing This makes the situation more complex, conceptually, than it actually is Although the underlying concept of each function is the same, you still have three names to remember This situation does not occur in C# because each absolute value method can use the same name Indeed, the NET Framework class library includes an absolute value method called Abs( ) This method is overloaded by the SystemMath class to handle the numeric types C# determines which version of Abs( ) to call based upon the type of argument A principal value of overloading is that it allows related methods to be accessed by use of a common name Thus, the name Abs represents the general action that is being performed It is left to the compiler to choose the right specific version for a particular circumstance You, the programmer, need only remember the general operation being performed Through the application of polymorphism, several names have been reduced to one Although this example is fairly simple, if you expand the concept, you can see how overloading can help manage greater complexity When you overload a method, each version of that method can perform any activity you desire There is no rule stating that overloaded methods must relate to one another However, from a stylistic point of view, method overloading implies a relationship Thus, while you can use the same name to overload unrelated methods, you should not For example, you could use the name Sqr to create methods that return the square of an integer and the square root of a floating-point value But these two operations are fundamentally different Applying method overloading in this manner defeats its original purpose In practice, you should only overload closely related operations C# defines the term signature, which is the name of a method plus its parameter list Thus, for the purposes of overloading, no two methods within the same class can have the same signature Notice that a signature does not include the return type since it is not used by C# for overload resolution Also, the params modifier is not part of the signature.

Jerk y'" =

= 5 (a)

Part I:

Like methods, constructors can also be overloaded Doing so allows you to construct objects in a variety of ways For example, consider the following program:

// Demonstrate an overloaded constructor using System; class MyClass { public int x; public MyClass() { ConsoleWriteLine("Inside MyClass()"); x = 0; } public MyClass(int i) { ConsoleWriteLine("Inside MyClass(int)"); x = i; } public MyClass(double d) { ConsoleWriteLine("Inside MyClass(double)"); x = (int) d; } public MyClass(int i, int j) { ConsoleWriteLine("Inside MyClass(int, int)"); x = i * j; } } class OverloadConsDemo { static void Main() { MyClass t1 = new MyClass(); MyClass t2 = new MyClass(88); MyClass t3 = new MyClass(1723); MyClass t4 = new MyClass(2, 4); ConsoleWriteLine("t1x: ConsoleWriteLine("t2x: ConsoleWriteLine("t3x: ConsoleWriteLine("t4x: } } " " " " + + + + t1x); t2x); t3x); t4x);

4 3 2 P

The output from the program is shown here:

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/4 0

Inside Inside Inside Inside MyClass() MyClass(int) MyClass(double) MyClass(int, int)

Substituting in Eq (250) gives Displacement from which we obtain Velocity Acceleration Jerk y = y = y = hp pq sin 2b b hp 2 pq cos 2b 2 b hp 3 pq sin 3 2b b (253) (254) (255) y= h pq 1 - cos , 2 b (252)

8:

t1x: t2x: t3x: t4x:

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