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There are several ways to get a Type object. We'll look at using the GetType method and using the typeof operator. Type object contains a method called GetType, which returns a reference to an instance s Type object. Since every type is ultimately derived from object, you can call the GetType method on an object of any type to get its Type object, as shown here: Type t = myInstance.GetType(); The following code shows the declarations of a base class and a class derived from it. Method Main creates an instance of each class and places the references in an array called bca for easy processing. Inside the outer foreach loop, the code gets the Type object and prints out the name of the class. It then gets the fields of the class and prints them out. Figure 24-2 illustrates the objects in memory. using System; using System.Reflection; class BaseClass { public int BaseField = 0; } class DerivedClass : BaseClass { public int DerivedField = 0; } class Program { static void Main( ) { var bc = new BaseClass(); var dc = new DerivedClass(); BaseClass[] bca = new BaseClass[] { bc, dc }; foreach (var v in bca) { Type t = v.GetType(); // Must use this namespace

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3. The next thing we need is a means to control our annotation. For that, we will create a UIViewController subclass that will control all the characteristics we want to display on this annotation. Click the Classes folder and enter N as shown in Figure 9 10. Because this controller will be in charge of controlling annotations for your position, name it myPos. Make sure that your options are not checked. These include Targeted for iPad, UITableViewController Subclass, and XIB Interface. This will automatically create a myPos header file and implementation file in your Classes folder once you hit the Next button or Return.

Finally, we re getting to the floating-point calculations. For the right part of Figure 5-17, you find that X=14 corresponds to Y=38.67. In reality, almost all interpolations will result in a floating-point value, and this approach is up to this task.





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Console.WriteLine("Object type : {0}", t.Name); FieldInfo[] fi = t.GetFields(); // Get the field info. foreach (var f in fi) Console.WriteLine(" Field : {0}", f.Name); Console.WriteLine(); } } }

Tip XNA provides functionality to do this interpolation for you if you want to interpolate Vector2s,

This code produces the following output: Object type : BaseClass Field : BaseField Object type : DerivedClass Field : DerivedField Field : BaseField

It s Already Working!

Vector3s, or Vector4s. For example, if you want to know which Vector2 is 70 percent between (5,8) and (2,9), you could use Vector2.Lerp(new Vector2(5,8), new Vector2(2,9), 0.7f).

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You can also use the typeof operator to get a Type object. Just supply the name of the type as the operand, and it returns a reference to the Type object, as shown here: Type t = typeof( DerivedClass ); Operator Type you want the Type object for The following code shows a simple example of using the typeof operator: using System; using System.Reflection; namespace SimpleReflection { class BaseClass { public int MyFieldBase; } class DerivedClass : BaseClass { public int MyFieldDerived; } class Program { static void Main( ) { Type tbc = typeof(DerivedClass); Console.WriteLine("Result is {0}.", tbc.Name); Console.WriteLine("It has the following fields:"); FieldInfo[] fi = tbc.GetFields(); foreach (var f in fi) Console.WriteLine(" {0}", f.Name); } } } This code produces the following output: Result is DerivedClass. It has the following fields: MyFieldDerived MyFieldBase // Must use this namespace

In the case of your terrain, for all (X,Z) values, you have defined a vertex for which you know the exact Y value. For all (X,Z) values between these discrete points, you don t know the exact Y value, so you ll have to do some kind of interpolation. This time, you will have to find a relative value between 0 and 1, both for X and for Z. Once you ve found these values, you can calculate the exact Y value in two steps, as shown in this recipe. Finding the Relative Values Given any (X,Z) coordinate, you need to find the exact height Y on your terrain. You start by finding the relative values for X and Z, using the formula discussed earlier. Only this time, you have to apply it two times because you re working in three dimensions: int xLower = (int)xCoord; int xHigher = xLower + 1; float xRelative = (xCoord - xLower) / ((float)xHigher - (float)xLower); int zLower = (int)zCoord; int zHigher = zLower + 1; float zRelative = (zCoord - zLower) / ((float)zHigher - (float)zLower); In your terrain, for each integer value of X and Z, you have defined a vertex, so you know the exact Y value at these points. So for any floating-point value of X, you find the lower X value by casting it to an int (for example, 2.7 will become 2). You find the higher X value by adding 1 to

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