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If you rest the cursor on the Constant Scan operator, you will see 14 values, as shown in Figure 11-2. The constants enumerate the visited partitions. Each partition is then accessed by Table Scan, as shown in Figure 11-3. The internally generated variable PtnIds1004 is assigned values 1, 2, 3. . ., 14 in the Constant Scan, and then each value is used as a parameter for the Table Scan operator.

Despite the non-normalized structure of HIGHWAYS_TEMP and the use of NULLs in the route specifiers of Highways, it s nonetheless possible to populate Highways with a single INSERT statement . Here is such a statement, which uses UNPIVOT (twice) to normalize the data and CASE to replace CTFIPS and STFIPS with NULL when required:

The preceding SQL Server showplan of a simple SELECT statement suggests that the lower levels of the engine (Storage Engine) perform scans and seeks knowing nothing about the partitioning above. They access each partition as if it is a new table after the Query Processor has translated a single partitioned table access into a join of a list of enumerated

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The optimal level in our scale is a nonclustered covering index defined with the orderid column as the key and all the other columns as included non-key columns: CREATE UNIQUE NONCLUSTERED INDEX idx_unc_oid_i_od_cid_eid_sid ON dbo.Orders(orderid) INCLUDE(orderdate, custid, empid, shipperid);

DECLARE @emptyLS GEOGRAPHY = geography::Parse('LINESTRING EMPTY'); INSERT INTO Highways SELECT CASE WHEN SIGNT = 'C' THEN CTFIPS END AS CTFIPS, CASE WHEN SIGNT IN ('C','S') THEN STFIPS END AS STFIPS, SIGNT, SIGNN, dbo.GeographyUnionAggregate(GEOG) AS GEOG, @emptyLS AS GEOM FROM ( SELECT CTFIPS, STFIPS, SIGNT1, SIGNN1, SIGNT2, SIGNN2, SIGNT3, SIGNN3, GEOG FROM HIGHWAYS_TEMP ) AS HT UNPIVOT ( SIGNT FOR SignTNum IN (SIGNT1, SIGNT2, SIGNT3) ) S UNPIVOT ( SIGNN FOR SignNNum IN (SIGNN1, SIGNN2, SIGNN3) ) as U WHERE RIGHT(SignTNum,1) = RIGHT(SignNNum,1) AND SIGNT IN ('I','U','C','S') AND GEOG IS NOT NULL GROUP BY CASE WHEN SIGNT = 'C' THEN CTFIPS END, CASE WHEN SIGNT IN ('C','S') THEN STFIPS END, SIGNT, SIGNN;

constants and parameterized table scans. Figure 11-4 shows the plan for the same statement against the same database in SQL Server 2008. Compared with the SQL Server 2005 plan in Figure 11-1, this plan is missing the Constant Scan enumerating partitions and the Nested Loops that performs the scan one partition after another.

The Table Scan properties are shown in Figure 11-5. Instead of the Partition ID we have only a True/False value for the Partitioned attribute. Observe that from the Estimated Execution Plan in SQL Server 2008, we cannot determine how many partitions the table has.

Next, we need to update the SRID value for each GEOG instance and add a constraint to enforce this SRID:

The plan's logic is similar to the previous one, only here, the ordered partial scan ends up reading fewer pages. That, of course, is because more rows fit in a leaf page of this index than data rows do in a clustered index page. You get the plan shown in Figure 3-54 .

We only know the table is partitioned. The apparent advantage of SQL Server 2005 Estimated Execution Plans disappears as soon as we have to work with hundreds of partitions or access several partitioned tables in a single query. The Actual Execution Plan in SQL Server 2008 does contain an Actual Partition Count attribute for every partitioned table scan and for every partitioned index scan or seek, as you can see in Figure 11-6. Before we start talking about statistics on partitioned tables and examining various examples of partition elimination, let s create a partitioned clustered index on our LINEITEMPART table:

------------------------------------------------------------Set the SRID of each GEOGRAPHY instance to 4326 (WGS 84) ----------------------------------------------------------UPDATE Highways SET GEOG.STSrid = 4326; GO ALTER TABLE Highways ADD CONSTRAINT enforce_geog_srid CHECK (GEOG.STSrid = 4326) GO

CREATE CLUSTERED INDEX L_IDX_SHIPDATE ON LINEITEMPART (L_SHIPDATE);

And here are the performance measures I got for this query: Logical reads: 9 CPU time: 0 ms Elapsed time: 47 ms Estimated subtree cost: 0.008086 Again, this is a trivial plan. And also here, the performance of the ordered partial scan will vary depending on the fragmentation level of the index. As you can see, the cost of the query dropped from 19.621100 in the lowest level in the scale to 0.008086, and the elapsed time from more than

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